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1. Given a list named days that contains "Monday", "Tuesday", "Wendesday",
"Thursday" and "Friday".
2. Correct the typo in "Wendesday" to "Wednesday" using the days list.
3. Print the list to ensure the change has been made.

Right Answer:

# Step 1 days = ["Monday", "Tuesday", "Wendesday", "Thursday", "Friday"] # Step 2 days[2] = "Wednesday" # Correcting the typo # Step 3 print(days) # Output: ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday']

1. Ask the user to provide three numerical inputs.
2. Create a tuple out of them.
3. If the sum of the first and second elements of the tuple is greater than the third, print
the tuple in reverse.
4. Otherwise, print the tuple normally.

Right Answer:

# Step 1 num1 = float(input("Enter first number: ")) num2 = float(input("Enter second number: ")) num3 = float(input("Enter third number: ")) # Step 2 num_tuple = (num1, num2, num3) # Step 3 and Step 4 if num1 + num2 > num3: print(num_tuple[::-1]) # Print the tuple in reverse else: print(num_tuple) # Print the tuple normally

1. Create a list named fruits containing the following items: "apple", "banana", "cherry".
2. Print the list to ensure it has been created correctly.
3. Create a tuple named vegetables containing the items: "carrot", "broccoli", "lettuce".
4. Print the tuple.

Right Answer:

# Step 1 fruits = ["apple", "banana", "cherry"] # Step 2 print(fruits) # Output: ['apple', 'banana', 'cherry'] # Step 3 vegetables = ("carrot", "broccoli", "lettuce") # Step 4 print(vegetables) # Output: ('carrot', 'broccoli', 'lettuce')

1. Create a list named mylist that contains ‘abc’, False, 1 and 3.14159.
2. Change False and 1 to True and 0 in one operation.
3. Extract the element ‘abc’ from the list and assign it to a variable in one operation.
4. Print that variable.
5. Assign the 3 list elements into 3 variables in one operation.
6. Print these variables.

Right Answer:

# Step 1 mylist = ['abc', False, 1, 3.14159] # Step 2 mylist[1:3] = [True, 0] # Change False and 1 to True and 0 # Step 3 abc_var = mylist.pop(0) # Extract 'abc' and assign it to abc_var print(abc_var) # Output: 'abc' # Step 4 var1, var2, var3 = mylist # Assign the remaining list elements to variables # Step 5 print(var1, var2, var3) # Output: True, 0, 3.14159

1. Given a tuple named months that contains "Jan", "Feb", "Mach” and "Apr"
2. Try to correct the typo in "Mach" to "March".
3. What happens?
4. Convert the tuple into a list.
5. Retry to correct the typo in "Mach" to "March".
6. Convert the list into a tuple.
7. Print the tuple.

Right Answer:

# Step 1 months = ("Jan", "Feb", "Mach", "Apr") # Step 2 # Trying to correct the typo will raise an error as tuples are immutable. # Step 3 - Explanation # Tuples are immutable, meaning we cannot change their items directly. # Step 4 months_list = list(months) # Converting tuple to list # Step 5 months_list[2] = "March" # Correcting the typo # Step 6 months = tuple(months_list) # Converting the list back to a tuple # Step 7 print(months) # Output: ('Jan', 'Feb', 'March', 'Apr')

1. Create a list named fishes that contains “catfish”, “perch”, “cod” and “carp”
2. Show the last element of the list using two different ways.
3. Change the second element of the list by another fish name.
4. Print the modified list.

Right Answer:

# Step 1 fishes = ["catfish", "perch", "cod", "carp"] # Step 2 print(fishes[-1]) # Output: carp (using negative index) print(fishes[3]) # Output: carp (using positive index) # Step 3 fishes[1] = "salmon" # Changing the second element to "salmon" # Step 4 print(fishes) # Output: ['catfish', 'salmon', 'cod', 'carp']

1. Create a list named values that contains 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10.
2. Slice the list such that you get every second element starting from the end, but not
including the last element.
3. Print the result (it should be 9, 7, 5, 3, 1).

Right Answer:

# Step 1 values = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # Step 2 sliced_values = values[-2::-2] # Slice to get every second element from the end, excluding the last element # Step 3 print(sliced_values) # Output: [9, 7, 5, 3, 1]

You can’t use any loop for this exercise.
1. Create a list named numbers that contains 3, 4, 5, 1 and 2.
2. Ask the user to input a number.
3. Compare the user's number to the maximum of the list.
4. Print whether it is higher or lower than the maximum of the list.
5. Do the same using another method.

Right Answer:

# Step 1 numbers = [3, 4, 5, 1, 2] # Step 2 user_number = int(input("Enter a number: ")) # Step 3 if user_number > max(numbers): print("Your number is higher than the maximum of the list.") else: print("Your number is lower than or equal to the maximum of the list.") # Step 5 - Alternative method maximum = sorted(numbers)[-1] # Sorting to find the max value if user_number > maximum: print("Your number is higher than the maximum of the list.") else: print("Your number is lower than or equal to the maximum of the list.")

1. Create a tuple that contains 0, 0, 1, 0, 1, and 1
2. Count the number of 0 using a method.
3. Find the index of the first 1 using a method.
4. Delete the tuple.
Tips: To delete a tuple, you could use del followed by the tuple name.

Right Answer:

# Step 1 binary_tuple = (0, 0, 1, 0, 1, 1) # Step 2 count_zeros = binary_tuple.count(0) print(count_zeros) # Output: 3 # Step 3 index_of_first_one = binary_tuple.index(1) print(index_of_first_one) # Output: 2 # Step 4 del binary_tuple # Deleting the tuple

1. Create a list named floats that contains 1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7 and 8.8
2. Use slicing to get the elements 2.2, 3.3 and 4.4 in one operation.
3. Use slicing to get the elements from 3.3 to the end of the list.
4. Use slicing to get the elements from the start of the list to 5.5 included.
5. Use slicing to reverse the list.

Right Answer:

# Step 1 floats = [1.1, 2.2, 3.3, 4.4, 5.5, 6.6, 7.7, 8.8] # Step 2 print(floats[1:4]) # Output: [2.2, 3.3, 4.4] # Step 3 print(floats[2:]) # Output: [3.3, 4.4, 5.5, 6.6, 7.7, 8.8] # Step 4 print(floats[:5]) # Output: [1.1, 2.2, 3.3, 4.4, 5.5] # Step 5 print(floats[::-1]) # Output: [8.8, 7.7, 6.6, 5.5, 4.4, 3.3, 2.2, 1.1]

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